2y^2-3x^2=6

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Solution for 2y^2-3x^2=6 equation: 


Simplifying
2y2 + -3x2 = 6

Reorder the terms:
-3x2 + 2y2 = 6

Solving
-3x2 + 2y2 = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y2' to each side of the equation.
-3x2 + 2y2 + -2y2 = 6 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-3x2 + 0 = 6 + -2y2
-3x2 = 6 + -2y2

Divide each side by '-3'.
x2 = -2 + 0.6666666667y2

Simplifying
x2 = -2 + 0.6666666667y2

Reorder the terms:
2 + x2 + -0.6666666667y2 = -2 + 0.6666666667y2 + 2 + -0.6666666667y2

Reorder the terms:
2 + x2 + -0.6666666667y2 = -2 + 2 + 0.6666666667y2 + -0.6666666667y2

Combine like terms: -2 + 2 = 0
2 + x2 + -0.6666666667y2 = 0 + 0.6666666667y2 + -0.6666666667y2
2 + x2 + -0.6666666667y2 = 0.6666666667y2 + -0.6666666667y2

Combine like terms: 0.6666666667y2 + -0.6666666667y2 = 0.0000000000
2 + x2 + -0.6666666667y2 = 0.0000000000

The solution to this equation could not be determined.

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